Check whether
3,
[tex]3 + \sqrt{2} [/tex]
,
[tex]3 + 2 \sqrt{2} [/tex]
,
[tex]3 + 3 \sqrt{2} [/tex]
are in arithmetic progression.
Share
Check whether
3,
[tex]3 + \sqrt{2} [/tex]
,
[tex]3 + 2 \sqrt{2} [/tex]
,
[tex]3 + 3 \sqrt{2} [/tex]
are in arithmetic progression.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Not are in arithmetic progression.
Step-by-step explanation:
Because different between two terms are not constant.
I solve it.
There are formula to solve
that is
d = t2 - t1
d =t3 - t2
d = t4 -t3
d is not constant.
Therefore it is not A.P.
please mark as brainliest answer.
[tex]\large\boxed{\fcolorbox{blue}{yellow} {Answer}}[/tex]
The given sequence is an Arithmetic Progression.
[tex]\large\boxed{\fcolorbox{blue}{yellow} {Step - by - step explanation }}[/tex]
The given sequence is
3, 3 + √2, 3 + 2√2, 3 + 3 √2
Now, here
t1 = 3,
t2 = 3 + √2,
t3 = 3 + 2 √2,
t4 = 3 + 3 √2
Now,
t2 - t1 = 3 + √2 - 3 = √2
t3 - t2 = (3 + 2√2) - (3 + √2) = 3 + 2√2 - 3 - √2 = √2
t4 - t3 = (3 + 3√2) - (3 + 2√2) = 3 + 3√2 - 3 - 2√2 = √2
Here, common difference d which is √2 is constant between two consecutive terms in the given sequence.
∴ The given sequence is an Arithmetic Progression.
Hope it helps!
[tex]<marquee> Mark as brainliest ✔️</marquee>[/tex]