[tex]\huge{\mathtt{\underline{\underline{\color{lavender}{Question}}}}}[/tex]
Find the area of shaded region of the figure given above.
with explanation
please don't delete my question..
Share
[tex]\huge{\mathtt{\underline{\underline{\color{lavender}{Question}}}}}[/tex]
Find the area of shaded region of the figure given above.
with explanation
please don't delete my question..
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Hey Blinky !!
Plz refer the pic .
Hope help ..
Thnx!!
Will you be my friend ??
Verified answer
Answer:
[tex]\pink{answer★}[/tex]
=Ar(ABCDEA)+ar(FGHF)+ar(HIDCJFH)
=Ar(semicircle ABC) - ar(semicircle AED)+ar(semicircle FGH)- ar (semicircle HID) - ar (semicircle FJC)
[tex]( \frac{1}{2}\pi \times \frac{21}{4} \times \frac{21}{4} ) - \: ( \frac{1}{2}\pi \times \frac{7}{2} \times \frac{ 7}{2} ) \\ \\ + ( \frac{1}{2}\pi \times \frac{7}{2} \times \frac{7}{2}) + ( \frac{1}{2}\pi \times \frac{35}{4} \times \frac{35}{4}) - \\ \\ ( \frac{1}{2}\pi \times \frac{7}{2} \times \frac{7}{2} )m {}^{2} [/tex]
[tex]( \frac{22}{7} \times \frac{441}{32}) + ( \frac{1}{2} \times \frac{22}{7} \times \frac{35}{4} \times \frac{35}{7} ) - \\ \\ ( \frac{22}{7} \times \frac{49}{8}) m {}^{2}[/tex]
[tex]( \frac{11 \times 63}{16}) + ( \frac{55 \times 35}{16} ) - \frac{77}{4} ) {m}^{2} = \\ ( \frac{693}{16} + \frac{1925}{16} - \frac{77}{4}) {m}^{2} [/tex]
[tex]( \frac{693 + 1925 - 308}{16} ) {m}^{2} [/tex]
[tex] = \frac{1115}{8} {m}^{2} = 144.38 {m}^{2} [/tex]
Answer of required Area=144.38m²