[tex]\large\mathbf{HEY\: QUESTION❤}[/tex]
In Figure, an equilateral triangle has been inscribed in a circle of radius 6 cm. Find the area of the shaded region. [Use π = 3.14]
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[tex]\large\mathbf{HEY\: QUESTION❤}[/tex]
In Figure, an equilateral triangle has been inscribed in a circle of radius 6 cm. Find the area of the shaded region. [Use π = 3.14]
★ PIC REFERS TO ATTACHMENT
★ REQUIRED QUALITY ANSWER
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Answer:
Given, Side of the equilateral triangle = 6 cm
And,
The area of the equilateral triangle
= √3/4(side)2
= √3/4(6)2
= √3/4(36)
= 9√3 cm2
Let us mark the center of the circle as O, OA and OB are the radii of the circle.
In triangle BOD,
sin 60o = BD/ OB
√3/2 = 3/ OB
OB = 2√3 cm = r
Therefore,
The area of shaded region = Area of the circle – area of the equilateral triangle
= πr2 – 9√3
= 3.14 x (2√3)2 – 9√3
= 3.14 x 12 – 9 x 1.732
= 37.68 – 15.588
= 22.092 cm2
Step-by-step explanation:
[tex]Hope \: it \: helps...!![/tex]
Answer:
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Step-by-step explanation:
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