[tex]1.2 + 2.3 + 3.4 + n(n + 1) = \frac{n(n - 1) \: (2n - 1)}{6} [/tex]
maths class 11
plz see solve it
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[tex]1.2 + 2.3 + 3.4 + n(n + 1) = \frac{n(n - 1) \: (2n - 1)}{6} [/tex]
maths class 11
plz see solve it
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Step-by-step explanation:
n(n+1)(2n+1)/6+n*(n+1)&2
Answer:
sorry I don,t know
Step-by-step explanation:
I am in 6