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No one is answering this question. i am posting it again. Hey, Physics Champs ! Help me to do this..
But Answer with proper Explanation is needed...
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#Figures was in the attachment .
In First figure CD and CE resistors are connected in series.
Rp = 1 Ω + 1Ω
Rp = 2Ω
Now, calculation resistance of two resistors of 2nd figure In which R1 and R2 resistors are in parallel.
So,
1/Rp = 1/R1 + 1/R2
1/Rp = 1/2 + 1/2
1/Rp = 2/2
Rp = 1Ω
Now, calculating resistance of 3rd figure in which two resistors are connected in series .
Rp = 1Ω + 1Ω
Rp = 2Ω
Calculating resistance of 4th figure in which LM and EF are connected in parallel.
1/Rp = 1/R1 + 1/R2
1/Rp = 1/2 + 1/2
1/Rp = 2/2
Rp = 1Ω
Calculating resistance of 5th figure in which 2 resistors are connected in series
Rp = 1Ω + 1Ω
Rp = 2Ω
Calculating resistance of 6th figure in which 2 resistors are connected in parallel.
1/Rp = 1/R1 + 1/R2
1/Rp = 1/2 + 1/2
1/Rp = 2/2
Rp = 1Ω
Calculating resistance of 7th figure in which two resistors are connected in series.
Rp = 1Ω + 1Ω
Rp = 2Ω
At last Calculating resistance of 8th figure in which resistors are connected in parallel.
1/Rp = 1/R1 + 1/R2
1/Rp = 1/2 + 1/2
1/Rp = 2/2
Rp = 1Ω
Hence,
Equivalent resistance of the given figure is 1Ω
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Answer:
I have posted the correct answer once.I am posting the answer with explanation again