answer the following questions step by step -
1)
[tex] x^{2} - 2 {}^{2} - 8[/tex]
2)
[tex]6x {}^{2} - 7x - 3[/tex]
3)
[tex]4u {}^{2} + 8u[/tex]
4)
[tex]3x {}^{2} - x - 4[/tex]
please answer the question properly spm will be deleted
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answer the following questions step by step -
1)
[tex] x^{2} - 2 {}^{2} - 8[/tex]
2)
[tex]6x {}^{2} - 7x - 3[/tex]
3)
[tex]4u {}^{2} + 8u[/tex]
4)
[tex]3x {}^{2} - x - 4[/tex]
please answer the question properly spm will be deleted
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Given Equation is x^2 - 2^2 - 8
= > x^2 - 12
(2)
Given 6x^2 - 7x - 3
= > 6x^2 + 2x - 9x - 3
= > 2x(3x + 1) - 3(3x + 1)
= > (2x - 3)(3x + 1).
(3)
Given 4u^2 + 8u
= > 4u(u + 2)
(4)
Given 3x^2 - x - 4
= > 3x^2 + 3x - 4x - 4
= > 3x(x + 1) - 4(x + 1)
= > (3x - 4)(x + 1).
Hope this helps!
Here is your answer,
_____________________________
1) x^2-2x-8=0
X^2 +2x -4x -8=0
X(x+2)-4(x+2)=0
(X+2)(x-4)=0
X+2=0
X=-2
X-4=0
X=4
_____________________________
2) 6x^2 -7x -3=0
6x^2 +2x-9x-3=0
2x(3x+1) - 3(3x+1)=0
(3x+1)(2x -3)=0
3x+1=0
X=-1/3
2x-3=0
X=3/2
_____________________________
3)4u^2-8u=0
4u(u-2)=0
4u=0
U=0
U-2=0
u=2
_____________________________
4)3x^2 -x-4=0
3x^2+3x -4x -4=0
3x(x+1)-4(x+1)=0
(3x -4)(x+1)=0
3x-4=0
X=4/3
X+1=0
X=-1
_____________________________
Hope it helps you!
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