[tex] 1 \div {x}^{2} + 3 = 1 \div 12[/tex]
please give me the answer of this question..
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[tex] 1 \div {x}^{2} + 3 = 1 \div 12[/tex]
please give me the answer of this question..
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Question :-
[tex] \rm \dfrac{1}{x^{2} + 3} = \dfrac{1}{12} \: find \: x[/tex]
Taking Square of x to right side Numerator as we can do cross Multiplication so, only I am taking Square of x in Numerator right side and keeping 3 down only in left side denominator. So, that becomes :-
[tex] \rm \dfrac{1}{3} = \dfrac{ {x}^{2} }{12} [/tex]
Now taking 12 to left side of equals so that it's help us to divide and How can we take it ? → As we can do cross Multiplication that's why we can do that
[tex] \rm \cancel\dfrac{12}{3} = \dfrac{ {x}^{2} }{1} [/tex]
[tex] \rm \: 4 = {x}^{2} [/tex]
Now if we do Square root in both side x will come
[tex] \rm\sqrt{ \: 4 }= \sqrt{{x}^{2} }[/tex]
[tex] \rm \: \bf 2 = \bf \: x[/tex]
or,
[tex] \rm \: \bf X = \bf \: 2[/tex]
[tex] \sf\therefore \: Value \: of \: x \: is \: \bf 2[/tex]
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