[tex]\huge\mathbb\red{Question}[/tex]
PLEASE SOLVE IT.......✌
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[tex]\huge\mathbb\red{Question}[/tex]
PLEASE SOLVE IT.......✌
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Answer:
[tex]a^x =b\\log(a^x) =logb\\x (loga)=logb\\x= \frac{logb}{loga} ..(1)\\and\\b^y=c\\log(b^y)=logc\\y =\frac{logc}{logb} ...(2)\\and\\c^z=a\\log(c^z) =loga\\z =\frac{loga}{logc} ...(3)\\then\\xyz=( \frac{logb}{loga})(\frac{logc}{logb})(\frac{loga}{logc})\\xyz=1[/tex]