[tex] \frac{2x-4+38y}{51x} + 78x = \frac{25x + 49y}{10y} [/tex]
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[tex] \frac{2x-4+38y}{51x} + 78x = \frac{25x + 49y}{10y} [/tex]
Please solve it fast!
Challenge for:-
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Verified answer
Answer:
y = 72899826.598
Step-by-step explanation:
[tex]\frac{2x-4+38}{51x} + 78x = \frac{25x+49y}{10y}[/tex]
⇒[tex]\frac{2x-4+38+3978x^{2} }{51x} = \frac{25x + 49y}{10y}[/tex]
⇒[tex]\frac{2x - 4+38+3978 \times x \times x}{51x} = \frac{25x + 49y}{10y}[/tex]
⇒[tex]\frac{2x+3978x \times x-4+38}{51x} = \frac{25x+49y}{10y}[/tex]
⇒[tex]\frac{3980x \times x-4+38}{51x} = \frac{25x+49y}{10y}[/tex]
⇒39800xy × 10xy - 40y + 380y = 1275x × x + 2499xy
⇒398000xy × xy - 40y + 380y = 1275x × x + 2499xy
⇒398000xy² - 40y + 380y = 1275x² + 2499xy
⇒398000xy² = 1275x² + 2499xy + 40y - 380y
⇒398000xy = [tex]\sqrt{1275x+2499xy+40y-380y}[/tex]
⇒398000xy = [tex]\sqrt{1275 \times x+2499 \times x \times y+40 \times y-380 \times y}[/tex]
⇒[tex]\frac{398000xy}{x}[/tex] = [tex]\sqrt{1275+2499\times x \times y+40 \times y - 380 \times y}[/tex]
⇒[tex]\frac{398000y}{y}[/tex] = [tex]\sqrt{1275+ 2499y+40y-380y}[/tex]
⇒398000 = [tex]\sqrt{1275+2539y-380y}[/tex]
⇒398000 = [tex]\sqrt{1275 + 2159y}[/tex]
⇒398000 - 1275 = [tex]\sqrt{2159y}[/tex]
⇒396725 = [tex]\sqrt{2159y}[/tex]
⇒2159y = (396725)²
⇒2159y = 157390725625
⇒y = 157390725625 ÷ 2159
⇒y = 72899826.598
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