[tex]( \frac{1 + {tan}^{2}A }{1 + {cot}^{2} A} ) = ( \frac{1 - tanA}{1 - cotA})^{2} = {tan}^{2}A[/tex]
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[tex]( \frac{1 + {tan}^{2}A }{1 + {cot}^{2} A} ) = ( \frac{1 - tanA}{1 - cotA})^{2} = {tan}^{2}A[/tex]
Prove
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