[tex]how \: \: much \: \: area \: \: ( in \: \: sq . \: \:units ) will \: a \: cube \: of volume \: a {}^{2} \: units \: cover \: on \: the \: floor[/tex]Solve it ⬆️⬆️⬆️⬆️
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[tex]how \: \: much \: \: area \: \: ( in \: \: sq . \: \:units ) will \: a \: cube \: of volume \: a {}^{2} \: units \: cover \: on \: the \: floor[/tex]Solve it ⬆️⬆️⬆️⬆️
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Answer:
Explanation:
The surface area of a cube = 6a2 where a is the length of the side of each edge of the cube. Put another way, since all sides of a cube are equal, a is just the lenght of one side of a cube.
We have 96 = 6a2 → a2 = 16, so that's the area of one face of the cube.
Solving we get √16, so a = 4
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Answer:
Oh sorry jay
I don't know that it was your real pic
BTW you are so stylish in this pic