the 17th term of an ap exceeds its 10th term by 7 find the common difference
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the 17th term of an ap exceeds its 10th term by 7 find the common difference
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Answer:
17th term = a+16d
10th term = a+9d
17th term - 10th term =7
a+16d -(a+9d) = 7
a+16d - a -9d = 7
7d =7
d=1
so, common difference is 1
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