The 17th term of an AP exceeds its 10th term by 7. Find the common difference
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The 17th term of an AP exceeds its 10th term by 7. Find the common difference
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Answer:
common difference is 1
Step-by-step explanation:
t17=t10+7
a+16d=a+9d+7
7d=7
d=1
Answer:
17th term = a+16d
10th term = a+9d
a+16d =a+9d+7
a-a + 16d-9d=7
7d=7
d=7/7
d=1
Step-by-step explanation: