the adjecent angles of a parallogram are(3x-13)°and (52+2x)°. find the angles of parallelogram......with solution
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the adjecent angles of a parallogram are(3x-13)°and (52+2x)°. find the angles of parallelogram......with solution
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Answer:
71.6°, 108.4°
Step-by-step explanation:
We know that the sum of adjacent angles of a parallelogram is 180°
Hence (3x - 13)° + (52 + 2x)° = 180°
⇒ (3x + 2x) + (52 - 13) = 180°
⇒ (5x + 39)° = 180°
⇒ 5x = 141°
⇒ x = (141/5)°
We know the angles are (3x - 13)°, (52 + 2x)°
Hence the angles are ((3*141/5) - 13) , (52 + (2*141/5))
= (358/5)°, (542/5)°
= 71.6° , 108.4°
Hence the angles are 71.6°, 108.4°
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Step-by-step explanation:
Sum of all angles of ||gm is 180°
ATQ
(3x-13)° + (52 +2x)° = 180°
(3x + 2x -13 + 52)° = 180°
(5x+39)° = 180°
5x = (180-39)°
x = 141/5°