the adjoining figure shows two boxes which box requires more material to make
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the adjoining figure shows two boxes which box requires more material to make
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Given : Adjoining figure shows two boxes
Box 1 : 60 cm * 70 cm * 50 cm
Box 2 : 60 cm * 60 cm * 60 cm
To Find : which box requires more material to make
Solution:
Assuming boxes are solid :
Then material required = volume of box
Box 1 : 60 cm * 70 cm * 50 cm
Volume = 60 * 70 * 50 = 210000 cm³
Box 2 : 60 cm * 60 cm * 60 cm
Volume = 60 * 60 * 60 = 216000 cm³
216000 > 210000
Hence Volume of Box > Volume of Box 1
=> Material required for Box 2 is more than for Box 1
Material required for Box 60 cm * 60 cm * 60 cm is more than for Box 60 cm * 70 cm * 50 cm
if empty box are made then surface area to be find
Surface area = 2(lb + bh + lh)
Box 1 : 60 cm * 70 cm * 50 cm = 2(60 * 70 + 60 *50 + 50*70) = 2(4200 + 3000 + 3500) = 2*10700 = 21400 cm²
Box 2 : 60 cm * 60 cm * 60 cm = 2( 60 * 60 + 60 *60 + 60*60) = 2(3600 + 3600 + 3600) = 2*10800 = 21600 cm²
Box 60 cm * 70 cm * 50 cm required less material in this case
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