the age of a man is twice the square of the ages of his sons . eight years hence the age of the man will be 4 years more than three time the age ohf his son find their present ages.
the age of a man is twice the square of the ages of his sons . eight years hence the age of the man will be 4 years more than three time the age ohf his son find their present ages.
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First take man's age = x then second case son's age = x
Solution:
Let the present age of son be years
Present age of his father years
Age of son after 8 years years
Age of his father after 8 years years
Given age of man will be 4 years more than 3 times his sons age.
Hence
2x^2+8=3x+28
2x^2-3x-20=0
2x^2-8x+5x-20=0
2x(x-4)+5(x-4)=0
(x-4)(2x+5)=0
x=4;x=-5/2
therefore x=4
therefore present age of son is 4 years
therefore present age of his father age 32 years