The age of two girls together is 15 years.one is 11 year older than the other. what is the age of younger one?
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The age of two girls together is 15 years.one is 11 year older than the other. what is the age of younger one?
Explain the answer
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Answer:
Age of the younger girl is 4 years
Explanation:
Given
To Find
Solution
Let age of younger girl = x
Age of older girl = x + 11
According to the Question
Age of younger girl + Age of older girl = 15
⟹ ( x ) + ( x + 11 ) = 15
⟹ x + x + 11 = 15
⟹ 2x + 11 = 15
⟹ x = 15 - 11
⟹ x = 4
Age of the younger girl = x = 4 years.
Given -
To find -
Solution -
In the question, we are provided, with the sum of ages of 2 girls, and one girl is elder than second one by 11 years, so first we will write the common ratio, then we will make the linear equation, then we will find the age of younger one.
So -
Let the age of younger one be x
Other girl is elder than her by 11 yrs, so x + 11
Now -
We will make a linear equation out of it, and then, we will take out the value of x, that is going to be the age of the younger one.
On substituting the values -
x + (x + 11) = 15
2x + 11 = 15
2x = 15 - 11
2x = 4
x =
x = 2 years
At the end -
Age of younger one is 2 yrs
Age of elder one is x + 11 = 2 + 11 = 13 yrs
Verification -
For verification, we will add up, both the age of younger and elder one.
2 + 13 = 15
15 = 15
Hence, verified
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