The area of a rectangular field is p^2 − 5p + 4.If its length is p−4. Then find its breadth.
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The area of a rectangular field is p^2 − 5p + 4.If its length is p−4. Then find its breadth.
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Answer:
Given : Rectangle length =(5p−6) m, width =(p+4) m and perimeter is 20 m.
We know that, perimeter of rectangle =2(length×breadth)
Then perimeter of rectangle =2[(5p−6)+(p+4)]=2(5p−6+p+4)=2(6p−2)
But given perimeter is 20 cm
∴2(6p−2)=20
⇒6p−2=10
⇒6p=10+2=12
⇒p=2
So width =(p+4)=2+4=6 m
Verified answer
Answer:
(p-1)
Step-by-step explanation:
Area of rectangle=p²-5p+4
Length of rectangle=p-4
Breath of rectangle=?(x)
Area of rectangle=length×breath
p²-5p+4=(p-4)×x
p²-4p-p+4=p-4×x
p(p-4)-1(p-4)=p-4×x
(p-4)(p-1)=p-4×x
x=p-1