The area of a square ABC is 49 cm Sq Find the area of the square obtained by joining the midpoint s of the sides of the square vkABCD
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The area of a square ABC is 49 cm Sq Find the area of the square obtained by joining the midpoint s of the sides of the square vkABCD
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Step-by-step explanation:
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Step-by-step explanation:
area of abcd =49cm²
construct a line pq joining the midpoints mo
let the midpoints mnop respectively
then, triangle pmq and reactangle abpq stands on same base between same parallel lines that's why
area (pmq) =½area (abpq) .......... equation 1
similarly area (opq) =½area (qpcd) ............equation 2
add equation 1 and equation 2
area (pmq +opq) =½area(abpq+qpcd)
area (mnop) =½area (abcd)
area (mnop) =49/2
area mnop =24.5cm²