# the area of a trapezium is 28 m?, and two parallel sides are 8 m and 60 dm
respectively, find the altitude.
1090 cm? and lengths of its parallel
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# the area of a trapezium is 28 m?, and two parallel sides are 8 m and 60 dm
respectively, find the altitude.
1090 cm? and lengths of its parallel
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Answer:
Area of trapezium =1/2*altitude*(sum of parallel sides)
60dm = 6m
Area of trapezium= 28 (given)
28 = 1/2*altitude*(6+8)
28=1/2*altitude*14
28= 7*altitude
altitude=4m
=4m Answer
Answer:
Step-by-step explanation:
Given
Area of trapezium =28m²
Two parallel sides=8m,60dm
Changing 60dm in meter
=6m (1m=10dm)
As we know area of trapezium =1/2 (sum of parallel lines) x altitude
28=1/2 x (8+6) x h
28=1/2x 14 x h
28=7 h
H=28/7 m
H=4m
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