the area of a triangle if a =51cm , b =70 and Angle C=41 degree is
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the area of a triangle if a =51cm , b =70 and Angle C=41 degree is
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Calculate the area of the triangle whose sides are 18 cm, 24 cm and 30 cm in length. Also find the length of the altitude corresponding to the smallest side.
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Solution
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Correct option is A)
According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is
A=
s(s−a)(s−b)(s−c)
where
s=
2
a+b+c
For the given triangle,
a=18 cm
b=24 cm
c=30 cm
s=
2
18+24+30
=36
A=
36(36−18)(36−24)(36−30)
A=
36×18×12×6
A=
216×216
=216 cm
2
Smallest side =18 cm
Area of the triangle =
2
1
×base×altitude=216
2
1
×18× altitude=216
Altitude =
9
216
=24 cm
Answer:
answer=24
Step-by-step explanation:
For the given triangle,
a=18 cm
b=24 cm
c=30 cm