The brakes applied to a car
produce an acceleration of 6 m s-² in the opposite direction to the motion. If the car takes 2 s to stop after the application of brakes, calculate the
distance it travels during this time.
plz don't spam
I need the correct answer with explanation :)
Share
Explanation:
Given:
Accerleration: a=−6 m/s2
Time t=2 s
Final velocity, v=0 m/s
v=u+at
0=u−6×2
u=12 m/s
s=ut+ 21 at 2
s=12×2+ 21
×(−6)×4
⇒s=12 m