The capacity of a parallel plate capacitor is 10 μF when the distance between its plates
is 9 cm. What will be its capacity if the distance between the plates is reduced by 6 cm.
i need solution of this problem please
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The capacity of a parallel plate capacitor is 10 μF when the distance between its plates
is 9 cm. What will be its capacity if the distance between the plates is reduced by 6 cm.
i need solution of this problem please
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Answer:
The capacitance of parallel plate capacitor is C=dAϵ0. where A= area of plate.
Thus, C∝d1
If d is halved then the capacitance will be doubled.
Hence the capacitance becomes C′=2C=2(10)=20μF
Explanation:
I hope it will help u
The capacitance of parallel plate capacitor is C=
d
Aϵ
0
. where A= area of plate.
Thus, C∝
d
1
If d is halved then the capacitance will be doubled.
Hence the capacitance becomes C
′
=2C=2(10)=20μF
Explanation: