The coordinates of the vertex (turning point of the parabolic graph) of the parabola
f(x) = 2x2 + px + q are (-3, 1), then
The value of p is
(A) 12
(C) 19
(B) -12
(D) -19
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The coordinates of the vertex (turning point of the parabolic graph) of the parabola
f(x) = 2x2 + px + q are (-3, 1), then
The value of p is
(A) 12
(C) 19
(B) -12
(D) -19
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Answer:
The value of [tex]p=12.[/tex]
Step-by-step explanation:
The given equation of parabola is [tex]$f(x)=2 x^{2}+p x+q[/tex] the coordinate of vertex is [tex]$(-3,1)$[/tex].
To find value of [tex]$p$[/tex].
We know that standard form of parabola is [tex]$y=a x^{2}+b x+c[/tex] the [tex]$x$[/tex] coordinate of the vertex is [tex]$\frac{-b}{2 a}$[/tex].
On comparing the given equation with the standard equation of parabola we have, [tex]$a=2, b=p$[/tex].
So, the [tex]$x$[/tex] coordinate is represented as:
[tex]$$\begin{aligned}&\frac{-p}{2(2)}=-3 \\&p=12\end{aligned}$$[/tex]
Therefore, the value of [tex]$p$[/tex] is [tex]$12 .$[/tex]
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