The diagonal of a field in the shape of a quadrilateral is 20m and the offsets to the diagonal
are 8m and 9m. Find its area.
Share
The diagonal of a field in the shape of a quadrilateral is 20m and the offsets to the diagonal
are 8m and 9m. Find its area.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Considering parallelogram as two symmetrical triangles with sides 40,60,80 metres
we have
Area of triange= Sqrt(s(s-40)(s-60)(s-80))
s=(40+60+80)/2=90
So area= Sqrt(90*(90-40)*(90-60)*(90-80))
=Sqrt(90*50*30*10)
=300*Sqrt(15)
Since there are two such triangle
Total area of parallelogram =2*300*Sqrt(15)
=600*Sqrt(15) m^2
Therefore the answer is 6)
Answer:
The diagonal of a quadrilateral is 16 m. If the offsets are 6 m and 8 m, the area of the quadrilateral = (16/2)(6+8) = 112 sq m. hope this helps
Step-by-step explanation: