The diagonals of a rhombus are 8cm and 15 cm. Write with STEPS.
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Answer:
let ABCD be a rhombus
diagonals :-
AC= 8cm
DB=15 cm
let AC and DB meet at a point O
AD² = AO² + OD²
AD² = 4² + 7.5²
AD² = 16 + 56.25
AD² = 72.25
AD = √72.56
AD = 8.5
HENCE, EACH SIDE OF THE RHOMBUS IS 8.5 CM....
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Answer:
The diagonals of a rhombus are 8 cm and 15 cm. Additional information: Its area = 8*15/2 = 60 sq cm. The distance between the opposites sides = 60/8.5 = 7.058823529 cm.
Step-by-step explanation:
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