The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is 11b+30
10b+30
11b+3
10b+3
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The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is 11b+30
10b+30
11b+3
10b+3
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Answer:
11b+30
Step-by-step explanation:
A 2 digit number is always defined as 10x+y where x and y are digits at tens and units place respectively
Digit at units place=b
Digit at Tens place=b+3
Therefore,
Number=10(b+3)+b
After opening the brackets,
Number=10b+30+b
=11b+30
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