The dimensions of a cuboidal tin box are 30cm ^ 40cm ^ 50cm. Find the tin required for 20 such boxes if the cost of tin sheet is Rs 25 per square meter
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The dimensions of a cuboidal tin box are 30cm ^ 40cm ^ 50cm. Find the tin required for 20 such boxes if the cost of tin sheet is Rs 25 per square meter
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Step-by-step explanation:
As we know that,
Surface area of cuboid =2(lb+bh+hl)
Therefore,
Surface area of 1 tin box
=2(30×40+40×50+50×30)
=2×(1200+2000+1500)
=9400cm
2
Surface area of 20 tin box =20×9400=188000cm
2
=18.8m
2
Given that the cost of the tin sheet is R.20 per square meter.
Therefore,
Cost of tin required for 20 tin boxes =20×18.8=Rs.376
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Step-by-step explanation:
As we know that,
Surface area of cuboid =2(lb+bh+hl)
Therefore,
Surface area of 1 tin box
=2(30×40+40×50+50×30)
=2×(1200+2000+1500)
=9400cm2
Surface area of 20 tin box =20×9400=188000cm2
=18.8m2
Given that the cost of the tin sheet is R.25per square meter.
Therefore,
Cost of tin required for 20 tin boxes =25×18.8
=Rs.470