The dimensions of a cuboidal tin box are 30cm ^ 40cm ^ 50cm. Find the tin required for 20 such boxes if the cost of tin sheet is Rs 25 per square meter
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The dimensions of a cuboidal tin box are 30cm ^ 40cm ^ 50cm. Find the tin required for 20 such boxes if the cost of tin sheet is Rs 25 per square meter
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Answer:
Surface area of cuboid =2(lb+bh+hl)
Therefore,
Surface area of 1 tin box
=2(30×40+40×50+50×30)
=2×(1200+2000+1500)
=9400cm
2
Surface area of 20 tin box =20×9400=188000cm
2
=18.8m
2
Given that the cost of the tin sheet is R.20 per square meter.
Therefore,
Cost of tin required for 20 tin boxes =20×18.8=Rs.376
Step-by-step explanation:
answer is above
hope it helps you
2(lb+bh+hl)
Therefore,
surface area of 1 tin box
= 2(30×40+40×50+50×30)
=2×(1200+2000+1500)
=9400cm^2
surface area of 20 tin box
=20×9400=188000cm^2
=18.8m^2
given that the cost of the tin sheet is Rs.20 per square meter
Therefore, cost of tin required for 20 tin boxes
=Rs.376.