The driver of a car travelling with a speed v suddenly applies brake. The speed is halved by the time the car travels a distance of 12m.How much further will the car travel before it comes to rest?
The driver of a car travelling with a speed v suddenly applies brake. The speed is halved by the time the car travels a distance of 12m.How much further will the car travel before it comes to rest?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Explanation:
See the image. Hope it helps. Please mark as brainliest pleaseeeee
Given:
For 1st case:
Initial velocity = v
Final velocity = v/2
Distance = 12 m
For 2nd case:
Initial velocity = v/2
Final velocity = 0
To Find:
The distance further covered by the car before it comes to rest.
Calculation:
- Applying third equation of motion to the first case we get:
v² = u² + 2as
(v/2)² = v² + 2 × a × 12
⇒ v²/4 - v² = 24 a
⇒ -3 v²/4 = 24 a
⇒ a = - v²/32
- Applying third equation motion to the second case, we get:
v² = u² + 2as
0² = (v/2)² + 2 × (- v²/32) × s
⇒ v² × s / 16 = v² / 4
⇒ s = 4 m
- So, the car will further travel 4 m before it comes to rest.