The enthalpy change for the reaction :
2NH,g) -> N2(g) + 3H2(g)
is 92.2 kJ. What is the enthalpy of formation of ammonia?
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The enthalpy change for the reaction :
2NH,g) -> N2(g) + 3H2(g)
is 92.2 kJ. What is the enthalpy of formation of ammonia?
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Answer:
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Explanation:
The enthalpy of formation of ammonia is −46.0 kJ mol −1 .
1/2 N2
+3/2 H 2
→NH 3
ΔH=−46.0kJ/mol
Multiply above equation with 2.N 2
+3H2
→2NH 3
ΔH=−46.0×2=−92.0kJ/mol
Reverse above equation
2NH 3
→N 2
+3H 2
ΔH=+92.0kJ/mol
The enthalpy change for the reaction 2NH3
→N 2
+3H 2
is 92.0 KJ mol −1
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