the fifth term in a sequence is 82 and the 12th is 103 find the first term and the common difference
the fifth term in a sequence is 82 and the 12th is 103 find the first term and the common difference
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
A5=82----------(1), A12=103-------------(2)
a+4d=82--------(3), a+11d=103-----------(4)
subtract equation 3 & 4
a+11d=103
a+4d=82
- - -
-----------------
7d=21
d=21/7=3
d=3
putting this value in equation 1st
a+4d=82
a+4(3)=82
a+12=82
a=82-12=70
therefore first term is 70, and common difference is 3
Answer:
first term,a = 70 and common difference,d =3
Step-by-step explanation:
Given:
a5= 82
a12=103
Explanation:
a5= a+4d
82=a+ 4d --- eqn 1
a12= a+11d
103= a+11d --- eqn 2
From equations 1 and 2 subtract 1 from 2
103=a+11d
82=a+4d
- - -
________
21=7d
d= 21/7
d=3
Putting d=3 in eqn 1 we have
a+4(3)=82
a+12=82
a=82-12
a=70
So, a=70 and d=3
AP is 70, -67, -64, -61........
PLEASE MARK AS BRAINLIEST!!!