The filament of a bulb takes a current 100 mA when potential difference across it is 0.2V . When the potential difference across it becomes 400mA . Calculate the resistance of the filament in each case and account for the difference............. PLS DONT GIVE ABSURB ANSWERS ........" I HAVE ASKED THIS QUESTION FOUR TIMES NOW AND HAVEN'T GOT A SINHLE ANSWER RIGHT....AND THIS IS MY LAST TRY"
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✒ R1 = 2Ω & R2= 2.5Ω
First case :-
⏩V1=I1 R1
⏩R1 = 0.2/0.1
➡ R1 =2Ω
Second Case :-
⏩V2 =I2 R2
⏩R2= 1/0.4
➡ R2 =2.5Ω
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Answer:
correct ANSWER ⬆️⬆️⬆️⬆️⬆️