the first three terms of an AP are 3y-1, 3y+5, 5y+1 respectively
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the first three terms of an AP are 3y-1, 3y+5, 5y+1 respectively
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The terms (3y – 1), (3y + 5) and (5y + 1) are in AP.
The value of y
The given 3 terms are in A.P
So,
Hence,the value of y is 5.
above answer is correct ✔✔✔