The focal length of a converging lens is 20cm. An object is 60cm from the lens. Where will be the image is formed. write the nature of the image
The focal length of a converging lens is 20cm. An object is 60cm from the lens. Where will be the image is formed. write the nature of the image
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since ,2F=40cm
It is given that object is kept at 60 cm from centre of curvature
since object at beyond 2F
nature of object =Real and Inverted
size of object =smaller than the object
position of object= Between the F and 2F on the other side of lens
Answer:
Given:
Object Distance (u) = - 60cm
Focal Length (f₁) = 20cm
To find: Image Distance (v)
From the Lens formula,
1/f = 1/v - 1/u
We get, v = f x u/ f + u
= v = 20 x (-60)/ 20 - 60
= 20 x 60/40 = 30cm
⇒ Image Distance = 30cm
∴ The image is formed in between F₁ and 2F₁.
Nature of the Image is (a) Real (b) Dimenished (c) Inverted
(ii) Given:
Height of the Object () = 2cm
To find: Height of the Image ()
We know that,
= = ⇒ = 30/-60 = 1/-2 ⇒ ⇒ = -1cm
∴ Height of the Image is 1cm, which is below the principal axis.
⇒ For more Clarification, you can observe the figure in the Attachment.