the force of attraction between two bodies at a certain separation is 10 N. What would be the force of attraction between them if the separation is halved?
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the force of attraction between two bodies at a certain separation is 10 N. What would be the force of attraction between them if the separation is halved?
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Answer:
The force of attraction is inversly proportional to the square of the distance between the objects. So if the distance of separation is reduced to half then the force will get quadrapuled. So the force between the objects is 40N now.
Answer:
40N
Explanation:
F₁ = (m₁m₂)/r² = 10N
F₂ = (m₁m₂)/ (r/2)² = (m₁m₂) x 4 /r² = 4 x 10N = 40N