The image of an object in a convex mirror is 4 cm from the mirror....radius of curvature is 24 cm find the object position and magnification....
EXPLANATION IS REQUIRED..........
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The image of an object in a convex mirror is 4 cm from the mirror....radius of curvature is 24 cm find the object position and magnification....
EXPLANATION IS REQUIRED..........
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Answer:
Given –
To Find –
Solution –
Mirror formula : 1/v + 1/v = 1/f
Substituting the values,
➸ 1/4 + 1/u = 1/12
➸ 1/u = 1/12 - 1/4
➸ 1/u = (4 - 12)/48
➸ 1/u = -8/48
➸ 1/u = -4/24
➸ 1/u = -1/6
➸ u = -6 cm
Hence, object distance is -6 cm.
We know, Magnification = -v/u.
Hence, M = -(4/-6)
➸ M = 4/6
➸ M = 2/3
➸ M = 0.6
Answer:
Explanation:
Given :-
Image Distance, v = 4 cm.
Radius of curvature, = 24 cm.
Focal length, f = 24/2 = 12 cm.
To Find :-
Object Distance, u = ??
Magnification, m = ??
Formula to be used :-
Mirror formula i.e 1/v + 1/v = 1/f
Magnification, m = - v/u = h'/h
Solution :-
Putting all the values, we get
Substituting the values,
1/4 + 1/u = 1/f
⇒ 1/u = 1/12 - 1/4
⇒ 1/u = (4 - 12)/48
⇒ 1/u = - 8/48
⇒ 1/u = - 4/24
⇒ 1/u = - 1/6
⇒ u = - 6 cm
Hence, object distance is 6 cm.
Now, Magnification, m = - v/u.
⇒ m = - (4/- 6)
⇒ m = 4/6
⇒ m = 2/3
⇒ m = 0.6
Hence, the magnification is 0.6.