the interior angles of a pentagon are x, 2x, 6x÷5, 12x÷5 and 12x÷5. Find all the angles of the Pentagon
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the interior angles of a pentagon are x, 2x, 6x÷5, 12x÷5 and 12x÷5. Find all the angles of the Pentagon
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The sum of all angles = (2n-4)90
= 540°.
then,
x +2x +1.2x + 2.4x + 2.4x = 540
3x + 6.0x = 540
9x = 540
x= 60
then
x = 60°
2x = 120°
1.2x = 1.2*60 = 72°
2.4x = 2.4*60= 144°
2.4x = 144°
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