The larger of two supplementary angles exceeds the smaller by18°.Find the angles.
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The larger of two supplementary angles exceeds the smaller by18°.Find the angles.
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hey..!
let one angle be x and another be x+18
so add them to get 180
means 2x+18=180
that means x is 81 and x+18is 99
so the angles are 81 and 99 which differs by 18degrees.
and smaller angle be y
now x = y + 18
also x+y = 180 - (1)
now put the vlaue of x in eq 1
y + 18+y = 180
2y =180 - 18 = 162
y = 162÷ 2 = 81
now y = 81
so x = y+ 18 = 81+18 =99