the LCM and HCF of two numbers are 432 and 72 respectively if one of the number is 216 what is the other
the LCM and HCF of two numbers are 432 and 72 respectively if one of the number is 216 what is the other
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Let one number is “a”=216 and the other number is “b” which is unknown as b=?
To find b we as
LCM=a×b/HCF
LCM ×HCF /a=b putting the value we get
432×72/216=b
Therefor:
b=144
So the other number is 144.
HCF*LCM= a*b
So,
432*72=216*b
b=31,104/216
b=144