the LCM of two numbers is 816 and their HCF is 3. If one of the number is 48, find the other.
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the LCM of two numbers is 816 and their HCF is 3. If one of the number is 48, find the other.
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WE KNOW THAT LCM × HCF = PRODUCT OF TWO NUMBERS
GIVEN
LCM = 816
HCF = 3
ONE NUMBER = 48
LET OTHER NUMBER BE 'X'
LCM × HCF = PRODUCT OF TWO NUMBERS
816 × 3 = 48 × X
2448 = 48X
X = 2448/48
X = 51
HENCE , THE OTHER NUMBER IS 51.
PLEASE MARK THIS AS THE BRAINLIEST ANSWER
Answer:
We know that H.C.F×L.C.M=product of the numbers.
Let the number be x
⇒ x = LCM × HCF
⇒ 816 × 3 = 48 × x
⇒ 24x = 3 × 316 = 17 × 3
∴ x = 51
Verfication
Lcm of 51 and 48 = 816
Hcf of 51 and 48 = 3
⇒ 816 ×