The length of a rectangle is 12 m more than twice the width. The area of the rectangle is 320 spuare meter. Write an equation that can be used to find the lenght and width of the rectangle. Also find the dimension of the rectangle.
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The length of a rectangle is 12 m more than twice the width. The area of the rectangle is 320 spuare meter. Write an equation that can be used to find the lenght and width of the rectangle. Also find the dimension of the rectangle.
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Answer:
Step-by-step explanation:
According to the Question
Let the breadth be x m
Then, the length be (2x + 12) m
It is given that the area of rectangle is 320 .
As we know that area of rectangle is calculated by the product of length and breadth .
Substitute the value we get
➻ x * (2x+12) = 320
➻ 2x² + 12x = 320
➻ 2x² + 12x -320 = 0
Taking Common 2
➻ x² + 6x -160 = 0
➻ x² + 16x -10x -160 = 0
➻ x (x+16) -10(x+16) = 0
➻ (x+16) (x-6) = 0
➻ x +16 = 0 or x-10 = 0
➻ x = -16 or x = 10
Since , dimension can't be negative .So the value of x is 10 m.
Length of rectangle = 2×6 + 12 = 12+12 = 24m