The length of a rectangle is 12 m more than twice the width. The area of the rectangle is 320 spuare meter. Write an equation that can be used to find the lenght and width of the rectangle. Also find the dimension of the rectangle.
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The length of a rectangle is 12 m more than twice the width. The area of the rectangle is 320 spuare meter. Write an equation that can be used to find the lenght and width of the rectangle. Also find the dimension of the rectangle.
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Step-by-step explanation:
Let breadth of the rectangle is x.
Then its length will be 2x−12
According to the problem,
2(length+breadth)=100
2(x+2x−16)=100
or, 6x=320
or, x=24.
Then length is
=2x−12
=48−12=36 cm.
Answer:
let the width be b m
so acc to question, length = 2(12+b) m
area = 320 sqm
Step-by-step explanation:
now, area of rect. = l*b
320 = b (24+2b)
320= 24b + 2b^2
solving the equation by quadratic formula,
b = 16 or b= -40
since breadth cant be negative, b= -40 is rejected so width = 16m
and accordingly length = 2(12+16) = 2*28= 54m
so the equation is 320= 24b + 2b^2
and dimensions are breadth = 16m and length = 54m
HOPE IT HELPS :D