the length of a rectangle is 2cm more than 3 times the width of the rectangle.if the perimeter of the rectangle is 28 cm ,find the dimensions of the rectangle
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the length of a rectangle is 2cm more than 3 times the width of the rectangle.if the perimeter of the rectangle is 28 cm ,find the dimensions of the rectangle
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Answer:
The width of the rectangle = x
The length of the rectangle = 2x
The perimeter = 22cm
now, we know that the perimeter of a rectangle is
2(l+b)
= 2(2x + x) = 22
= 2(3x) = 22
= 6x = 22
x =22/6
x = 11/3
now the width of rectangle = 11/3
the length is twice than width so,
= 11/3x2
= 22/3cm
the length of the rectangle is 22/3 cm.
Step-by-step explanation:
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Step-by-step explanation:
Given:-
the length of a rectangle is 2cm more than 3 times the width of the rectangle.if the perimeter of the rectangle is 28 cm
To find:-
find the dimensions of the rectangle.
Solution:-
Let the breadth of the rectangle be 'b' cm
Then the length of the rectangle =the length of a rectangle is 2cm more than 3 times the width of the rectangle
=>length=(3b+2) cm
Perimeter of the rectangle =
2(length+breadth) units
=>2(3b+2+b) cm
=>2(4b+2) cm
=>8b+4 cm
According to the given problem,
the perimeter of the rectangle is 28 cm
=>8b+4=28
=>8b=28-4
=>8b=24
=>b=24/8
=>b=3cm
l=3b+2=3(3)+2=9+2=11cm
Answer:-
Length of the rectangle =11 cm
Breadth of the rectangle=3 cm