The length of a rectangle is twice its breadth. If its perimeter is 60 cm, find the length and the breadth of the rectangle.
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The length of a rectangle is twice its breadth. If its perimeter is 60 cm, find the length and the breadth of the rectangle.
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Step-by-step explanation:
Given:-
To find:-
Solution:-
Let, Breadth of rectangle be 'x'.
And Length of rectangle be '2x'.
We know that,
[tex] \boxed{\sf \bold{\star \: Perimeter \:of\: rectangle = 2(l + b)}} [/tex]
In which,
Perimeter = 60 cm.
Put perimeter in formula :
[tex] \longrightarrow \sf 60 = 2\times (2x + x) [/tex]
[tex] \longrightarrow \sf 60 = 4x + 2x [/tex]
[tex] \longrightarrow \sf 60 = 6x[/tex]
[tex] \longrightarrow \sf \cfrac{60}{6} = x [/tex]
[tex] \longrightarrow \sf 10 = x [/tex]
Or, x = 10
We have taken x be Breadth. So, Breadth is 10 cm.
And We have taken length be 2x = 2×10 = 20 cm. Therefore, Length of rectangle is 20 cm.
Answer:
[tex]here \: is \: your \: answer[/tex]
Length of a Rectangle = 2breadth
[tex]l = 2b[/tex]
[tex]perimeter \: of \: rectangle \: = 2(l + b)[/tex]
[tex]60 = 2(2b + b)[/tex]
[tex] \frac{60}{6} = b[/tex]
[tex]10 = b[/tex]
[tex]60 = 2(3b)[/tex]
[tex]60 = 6b[/tex]
[tex]10 = b[/tex]
Hence the breadth of rectangle is 10cm
[tex]length = 2 \times 10 = 20cm[/tex]
Hence the length of rectangle is 20 cm