the length of the diagonal of a quadrilateral is 40 cm and the perpendicular drawn to it from the opposite vertices are 12 cm and 7.5 cm find the area of the quadrilateral
the length of the diagonal of a quadrilateral is 40 cm and the perpendicular drawn to it from the opposite vertices are 12 cm and 7.5 cm find the area of the quadrilateral
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Then ac=40
Broke the quad. into two ∆
So ar(abc)=0.5*40*12=240cm
And ar(ADC)=0.5*40*7.5=150cm
Ar(abcd)=240+150=390cm
Answer:390cm
Step-by-step explanation:
Let abcd be a quadrilateral
AC=40cm
A quadrilateral=2 triangles
So area of ABC=0.5*40*12=240cm
And area of ACD=0.5*40*7.5=150cm
AREA OF ABCD=240+150=390cm