The length of the diagonals of a rhombus are 24cm and 10cm. Find the perimeter.
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The length of the diagonals of a rhombus are 24cm and 10cm. Find the perimeter.
I already know the answer. I just want someone to answer the question in proper and complete statements.
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Answer:
Here, AC = 24 cm and BD = 10 cm, therefore, AO = 12 cm and BO = 5 cm.
Now to find the perimeter, we need the length of AB.
Let’s find AB using the pythagoras theorem in ABC,
AB2 = AO2 + OB2
AB2 = 122 + 52
AB2 = 144 + 25
AB2 = 169
AB = √169
AB = 13 cm
Since the length of one side of the rhombus is AB = 13cm, perimeter of the rhombus, P = 4 × side of a rhombus
P = 4 × AB
P = 4×13 = 52 cm
Thus, perimeter of the rhombus is 52 cm.
Step-by-step explanation:
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