The length of
a
rectangle is 20% more than
breadth. What will be the ratio of area
of rectangle to that of
of a square .
whose side
is equal to the breadth of the
rectangle.
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The length of
a
rectangle is 20% more than
breadth. What will be the ratio of area
of rectangle to that of
of a square .
whose side
is equal to the breadth of the
rectangle.
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Answer:
The answer is 6:5
Step-by-step explanation:
Let be breadth be x
length = 20/100 * 'x'
= x/5 + x (because length is x/5 more than the breadth so x/5 + x)
area of rectangle is = L x B
= (x/5 + x) x (x)
= (6x/5) x (x) (LCM of x/5 +x)
= 6x²/5
side of square(S) = x
area of square = x²
ratio of the both areas = (6x²/5)/x²
= (6x²/5) x (1/x²)
= 6/5 (x² be cancelled)
so the ratio is 6:5
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