The man bought a mirror of area 0.3m² whose width is 40cm,the find the length of the mirror.
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The man bought a mirror of area 0.3m² whose width is 40cm,the find the length of the mirror
The man bought a mirror of area 0.3m² whose width is 40cm,the find the length of the mirror.
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Answer:
V±ΔV=(2.7±0.14)m
3
Here, m±Δm=(12.4±0.1) kg
and, p±Δp=(4.6±0.2)kg/m
3
Volume, v=
p
m
=
4.6
12.4
=2.69m
3
=2.7m
3
(rounding off to one decimal place )
Now,
V
ΔV
=±(
m
Δm
+
p
Δp
)
ΔV=±(
m
Δm
+
p
Δp
)×V
=±(
12.4
0.1
+
p
0.2
)×2.7=±0.14
∴V±ΔV=(2.7±0.14)m
3
Verified answer
Answer:
75cm
Explanation:
area of mirror = width x length
0.3m² = 40cm x length
0.3x10000cm²r 40cm x length
3000cm2 = 40cm x length
length = 3000/40cm = 75cm.