The mass of a simple pendulum bob is 100 gm. The length of the pendulum is 1 m. The bob is drawn aside from the equilibrium position so that the string makes an angle of 60° with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be
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The mass of a simple pendulum bob is 100 gm. The length of the pendulum is 1 m. The bob is drawn aside
Answer:
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Explanation:
K.E
A
=Δ P.E. b/w A & B
=mg(L−Lcos60
0
)
=10
−1
×9.8×(1−
2
1
)
=0.49J
Answer:
=10
−1
×9.8×(1−
2
1
)
=0.49J
Explanation:
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